Question
Question: If the lines 4x + 3y – 1 = 0, x – y + 5 = 0 and kx + 5y – 3 = 0 are concurrent, then k is equal to...
If the lines 4x + 3y – 1 = 0, x – y + 5 = 0 and kx + 5y – 3 = 0 are concurrent, then k is equal to
A
4
B
5
C
6
D
7
Answer
6
Explanation
Solution
41k3−15−15−3 = 0 Ž k = ?