Question: If the line $x + 2 b y + 7 = 0$ is a diameter of the circle \(x ^ { 2 } + y ^ { 2 } - 6 x + 2 y...

Question

If the line $x + 2 b y + 7 = 0$ is a diameter of the circle $x ^ { 2 } + y ^ { 2 } - 6 x + 2 y = 0$ then b =

Answer 1

Here the centre of circle (3, –1) must lie on the line Therefore, $3 - 2 b + 7 = 0 \Rightarrow b = 5$

Question: If the line \(x + 2 b y + 7 = 0\) is a diameter of the circle \(x ^ { 2 } + y ^ { 2 } - 6 x + 2 y...