If the line (2x+\sqrt6y=2) touches the hyperbola x2 - 2y2 =... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

If the line $2x+\sqrt6y=2$ touches the hyperbola x2 - 2y2 = 4, then the point of contact is

A

$(-4,\sqrt6)$

B

$(-4,-\sqrt6)$

C

$(4,-\sqrt6)$

D

$(4,\sqrt6)$

Answer

$(4,-\sqrt6)$

Explanation

Solution

The correct option is (C) : $(4,-\sqrt6)$ .