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Question

Question: If the length of tangent drawn from the point (5, 3) to the circle \(x ^ { 2 } + y ^ { 2 } + 2 x + k...

If the length of tangent drawn from the point (5, 3) to the circle x2+y2+2x+ky+17=0x ^ { 2 } + y ^ { 2 } + 2 x + k y + 17 = 0be 7, then k =

A

4

B

– 4

C

– 6

D

13/2

Answer

– 4

Explanation

Solution

According to the condition,

(5)2+(3)2+2(5)+k(3)+17=7\sqrt { ( 5 ) ^ { 2 } + ( 3 ) ^ { 2 } + 2 ( 5 ) + k ( 3 ) + 17 } = 7

\Rightarrow 61+3k=49k=461 + 3 k = 49 \Rightarrow k = - 4.