Question

If the length of second pendulum is increased by 21%. How many oscillations it will lose per day

• A. 3927
• B. 3722
• C. 34273
• D. None of these

Answer 1

Answer: (A)

3927

Answer 2

T µ $\sqrt { \ell }$

$\sqrt { \frac { \ell _ { 2 } } { \ell _ { 1 } } }$ Ž T₂ = 1.1

T₁ = 2.2 sec

Initial no. of oscillation = $\frac { 86400 } { 2 }$ = 43200

final no. of oscillation = $\frac { 86400 } { 2.2 }$ = 39273

no. of lost oscillations = 43200 – 39273 = 3927