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Question

Physics Question on physical world

If the length of rod AA is 3.25±0.01cm3.25\pm 0.01\,cm and that of BB is 4.19±0.01cm,4.19\pm 0.01\,cm, then the rod BB is longer than rod AA by

A

0.94±0.00cm0.94\pm 0.00\,cm

B

0.94±0.01cm0.94\pm 0.01\,cm

C

0.94±0.02cm0.94\pm 0.02\,cm

D

0.94±0.005cm0.94\pm 0.005\,cm

Answer

0.94±0.02cm0.94\pm 0.02\,cm

Explanation

Solution

Length of rod AA is
LA=3.25±0.01L_A = 3.25 \pm 0.01
and that of BB is
LB=4.19±0.01L_B = 4.19 \pm 0.01
Then, the rod BB is longer than rod AA by a length
l=LBLA\triangle l = L_B - L_A
l=(4.19±0.01)(3.25±0.01)\triangle l = ( 4.19 \pm 0.01) - ( 3.25 \pm 0.01)
l=(0.94±0.02)cm\triangle l = ( 0.94 \pm 0.02 ) cm