Question: If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s, then the frequency f...

Question

If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s, then the frequency for the second note is

Answer 1

For closed pipe second note

= $\frac{3v}{4l} = \frac{3 \times 330}{4 \times 1.5} = 165Hz$ .