Question

If the kinetic energy of the particle is increased by 16 times, the percentage change in the de-Broglie wavelength of the particle is –

• A. 25%
• B. 75%
• C. 60%
• D. 50%

Answer 1

Answer: (B)

75%

Answer 2

l =$\frac{h}{\sqrt{2mE}}$

l¢ =$\frac{h}{\sqrt{2m \times 16}}$

l =$\frac{\lambda}{4}$

% change =$\frac{\frac{\lambda}{4} - \lambda}{\lambda}$× 100%

= – 75%