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Question

Physics Question on Kinetic Energy

If the kinetic energy of a body becomes four times of its initial value, then new momentum will

A

become four times, its initial value

B

become three times, its initial value

C

become twice its initial value

D

ramains constant

Answer

become twice its initial value

Explanation

Solution

The kinetic energy of a body of mass mm and velocity vv is E=12mv2=p22mE=\frac{1}{2} m v^{2}=\frac{p^{2}}{2 m} where p=mv=p=m v= momentum of the body p2E=2m=\therefore \frac{p^{2}}{E}=2 m= constant m=\because m= constant p12El=p22E2\frac{p_{1}^{2}}{E_{ l }}=\frac{p_{2}^{2}}{E_{2}} Now, E2=4E1E_{2}=4 E_{1} p12p22=14\therefore \frac{p_{1}^{2}}{p_{2}^{2}}=\frac{1}{4} p1p2=12p2=2p1\Rightarrow \frac{p_{1}}{p_{2}}=\frac{1}{2} \Rightarrow p_{2}=2 p_{1}