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Question: If the ionization energy of hydrogen atom is \(13.6\) eV, the energy required to excite it from grou...

If the ionization energy of hydrogen atom is 13.613.6 eV, the energy required to excite it from ground state to the next higher state is approximately.

A

3.4eV3.4eV

B

10.2eV10.2eV

C

17.2eV17.2eV

D

13.6eV13.6eV

Answer

3.4eV3.4eV

Explanation

Solution

: En=E1n2E_{n} = \frac{- E_{1}}{n^{2}}

En1=13.6;En2=13.64=3.4eVE_{n1} = 13.6;E_{n_{2}} = \frac{13.6}{4} = 3.4eV