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Chemistry Question on Some basic concepts of chemistry

If the ionisation energy and electron affinity of an element are 275275 and 86 kcal mol−186 \,kcal\, mol^{-1} respectively, then the electronegativity of the element on the Mulliken scale is

A

2.8

B

0

C

4

D

2.6

Answer

2.8

Explanation

Solution

According to Mulliken, electronegativity of an atom is average of ionization energy and electron affinity (in eV).
\cenm=IE+EA2\ce{ n_m = \frac{IE + EA}{2}}
If ionization energy and electron affinity are in kcal mol−1kcal\,mol^{-1}.
\cen=IE+EA125=275+86125=288\ce{n = \frac{IE + EA}{125} = \frac{275 + 86}{125} = 288}