Question

If the intermolecular forces vanish away, the volume occupied by the molecules contained in 4.5 kg water at standard temperature and pressure will be given by

• A. $5.6m^{3}$
• B. $\mathbf{4.5}\mathbf{m}^{\mathbf{3}}$
• C. 11.2 litre
• D. $\mathbf{11.2}\mathbf{m}^{\mathbf{3}}$

Answer 1

Answer: (A)

$5.6m^{3}$

Answer 2

$\mu = \frac{\text{Mass of water}}{\text{Molecular wt. of water}} = \frac{4.5kg}{18 \times 10^{- 3}kg} = 250$,

T = 273 K and $P = 10^{5}N ⥂ / ⥂ m^{2}$ (STP)

From $PV = \mu RT$

⇒ $V = \frac{\mu RT}{P} = \frac{250 \times 8.3 \times 273}{10^{5}} = 5.66m^{3}$.