Question
Question: If the intensity of sound is increased by a factor of \[30\], by how many decibels is the sound leve...
If the intensity of sound is increased by a factor of 30, by how many decibels is the sound level increased?
A) 12dB
B) 14.77dB
C) 10dB
D) 13dB
Solution
Sound Intensity, also known as acoustic intensity, is the power the sound wave carries per unit area in a direction perpendicular to the aforementioned area. Decibel, on the other hand, is a logarithmic unit, used to measure sound level.
Formula used: β=10logI0I
Complete step by step solution:
We have been given that intensity of sound increases by a factor of 30
One decibel is equal to ten times the logarithm to base 10 (or common logarithm) of the power or the intensity ratio. It can be more clearly expressed as a formula,
β=10logI0I where β is the sound level in decibels, I is the intensity of sound and I0 is the threshold intensity of sound.
Let the initial intensity of the sound be I, we can express it in decibels as β1=10logI0I
Now, the intensity of sound is increased by a factor of 30, so the new intensity of the sound will be 30I. The loudness of this intensity can be expressed as β2=10logI030I
Since we are concerned with the increase in the loudness, we can find it by taking the difference between the two calculated decibel loudness,
Increase in sound level ⇒β2−β1
β2−β1=10logI030I−10logI0I
Using properties of logarithms, we can now say that