Solveeit Logo

Question

Question: If the inclination of line \( \left( {2 - k} \right)x - \left( {1 - k} \right)y + \left( {5 - 2k} \r...

If the inclination of line (2k)x(1k)y+(52k)=0\left( {2 - k} \right)x - \left( {1 - k} \right)y + \left( {5 - 2k} \right) = 0 is 3π4\dfrac{{3\pi }}{4} , then the value of k is
A. 52\dfrac{5}{2}
B. 32\dfrac{-3}{2}
C. 23\dfrac{2}{3}
D. 32\dfrac{3}{2}

Explanation

Solution

Hint : The angle inclination of a line is the angle formed by the intersection of the line and X- axis. Find the slope of the line using a tangent of angle. Then find the slope of the line in terms of coefficients of xx and yy . Both the slopes must be the same. Use this to find the value of kk .

Complete step by step solution:
It is given that the inclination of line
L(2k)x(1k)y+(52k)=0L \equiv \left( {2 - k} \right)x - \left( {1 - k} \right)y + \left( {5 - 2k} \right) = 0 is 3π4\dfrac{{3\pi }}{4}

Let the slope of the given line =m= m
We know that, The slope of line =tanθ= \tan \theta
m=tanθ\therefore m = \tan \theta
Put the value of θ\theta in above equation,
We get, m=tan3π4=1m = \tan \dfrac{{3\pi }}{4} = - 1
1=k2k1- 1 = \dfrac{{k - 2}}{{k - 1}} . . . . (tanθ=yx)\left( {\tan \theta = \left| {\dfrac{y}{x}} \right|} \right)
k1=2k\Rightarrow k - 1 = 2 - k . . . . (By cross multiplication)
k=32\Rightarrow k = \dfrac{3}{2} . . . . (On simplifying the above equation)
Therefore, from the above explanation, the correct option is (D) 32\dfrac{3}{2} .
So, the correct answer is “Option D”.

Note : Inclination is the angle between two lines or planes where it intersects each other; the inclination of one line to another is measured in degrees or radians. The slope of the line using tangent of an angle is equal to the slope of the line using the coefficients of xx and yy , because both of them represent the slope of the same line.