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Question

Mathematics Question on Hyperbola

If the hyperbola x2y2cosec2θ=5x² - y² cosec²θ = 5 and ellipse x2cosec2θ+y2=5x²cosec²θ + y² = 5 has eccentricity eHe_H and eEe_E respectively and eH=7eEe_H = \sqrt 7e_E, then θθ is equal to

A

π6\frac \pi6

B

π3\frac \pi3

C

π2\frac \pi2

D

π4\frac \pi4

Answer

π6\frac \pi6

Explanation

Solution

The correct option is (A): π6\frac \pi6.