Question
Question: If the heat of combustion of ethanol is \(1367kJmo{l^{ - 1}}\) , how would you calculate the theoret...
If the heat of combustion of ethanol is 1367kJmol−1 , how would you calculate the theoretical mass of ethanol required to heat 200mL of water from 21.00 to 450 ?
Solution
To solve this question we must apply the formula for specific heat capacity or also called as specific heat. First we need to know what specific heat capacity is. Heat capacity of a substance is the quantity of the heat which is required to raise the temperature of the entire substance by one degree. If the mass of the substance is unity then the heat capacity is called a specific heat capacity or the specific heat.
Complete step-by-step answer: In order to solve this problem first we must find out how much energy is involved in heating the water.
For that the energy equation is given as
E=m⋅c⋅θ
Where, E is the energy we have to find out which is in Joules.
m is the mass in kilograms, so we have to convert 200mL to kilograms therefore 200divided by 1000 hence we must substitute 0.2kg
c is the specific heat of water which is 4186J/kg
θ is the temperature increase which is the difference between 450 and 21.00 which is 240
Thereby by substituting the values we get,