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Question

Physics Question on Heat Transfer

If the heat of 110J110\,\,J is added to a gaseous system, whose internal energy is 40J40\,\,J , then the amount of external work done is:

A

180J180\,\,\text{J}

B

70J70\,\,\text{J}

C

110J110\,\,\text{J}

D

30J30\,\,\text{J}

Answer

70J70\,\,\text{J}

Explanation

Solution

Heat added to the system ΔQ=110J\Delta Q=110 \,J
Internal energy ΔU=40J\Delta U=40\, J
External work done is given by
ΔW=ΔQΔU=11040\Delta W=\Delta Q-\Delta U=110-40
=70J= 70 \,J