Question

If the heat change at constant volume for decomposition of silver oxide is $80.25$ kJ. What will be the heat change at constant pressure?

• A. $80.25kJ$
• B. $> 80.25kJ$
• C. $< 80.25kJ$
• D. $160.50kJ$

Answer 1

Answer: (B)

$> 80.25kJ$

Answer 2

: $AgO_{(g)} \rightarrow 2Ag_{(g)} + \frac{1}{2}O_{2(g)};q_{v} = \Delta U = 80.25kJ$

$q_{P} = q_{v} + \Delta n_{g}RT$

$\Delta n_{g} > 0\left( \frac{1}{2} - 0 = \frac{1}{2} \right)$ or $q_{P} > q_{v}$or $q_{p} > 80.25kJ$