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Question

Physics Question on Nuclei

If the half-life of any sample of radioactive substance is 44 days, then the fraction of sample will remain undecayed after 22 days, will be?

A

2\sqrt{2}

B

12\frac{1}{\sqrt{2}}

C

212\frac{\sqrt{2}-1}{\sqrt{2}}

D

12\frac{1}{2}

Answer

12\frac{1}{\sqrt{2}}

Explanation

Solution

From Rutherford-Soddy law, the fraction left after nn half-lives is N=N0(12)nN=N_{0}\left(\frac{1}{2}\right)^{n} where nn is number of half-lives. n= time (t) half-life (T1/2)=24=12n=\frac{\text { time }(t)}{\text { half-life }\left(T_{1 / 2}\right)}=\frac{2}{4}=\frac{1}{2} NN0=(12)1/2\therefore \frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{1 / 2} NN0=12\Rightarrow \frac{N}{N_{0}}=\frac{1}{\sqrt{2}}