Question

If the gravitational force between two objects were proportional to 1/R (and not as $\left. 1 / R ^ { 2 } \right)$ where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to

• A. $1 / R ^ { 2 }$
• B. $R ^ { 0 }$
• C. $R ^ { 1 }$
• D. 1/R

Answer 1

Answer: (B)

$R ^ { 0 }$

Answer 2

Gravitational force provides the required centripetal force for orbiting the satellite

$\frac { m v ^ { 2 } } { R } = \frac { K } { R }$ because $\left( F \propto \frac { 1 } { R } \right)$

∴