Question

If the gravitational field in the space is given as $\left(-\frac{K}{r^2}\right)$ Taking the reference point to be at $r =2\, cm$ with gravitational potential $V =10 \,J / kg$ Find the gravitational potential at $r =3\, cm$ in SI unit (Given, that $K =6 \,Jcm / kg$ )

• A. 11
• B. 10
• C. 12
• D. 9

Answer 1

Answer: (B)

10

Answer 2

−drdV​=−r2k​⇒10∫V​dV=2∫3​r2k​dr
V−10=k[21​−31​]
V−10=6k​⇒V=11 volts