Question

If the general formula for aldehyde is written as ${C_n H_{2n+1}CHO}$, the value of n for isobutyraldehyde is

• A. 1
• B. 3
• C. 4
• D. 5

Answer 1

Answer: (B)

3

Answer 2

Total number of $C$ atoms in isobutyraidehyde $(CH_3)_2CHCHO$ is four, $\therefore$ Value of n should be $3$ in $C_nH_{2n+1} CHO$. This reaction involves acylation. $CH_3COCH_3$ is not an acetylating agent.