Solveeit Logo

Question

Question: If the formula for the sine of a sum of angles C and D is given by \(\sin (C+D)=\sin C.\cos D+\cos...

If the formula for the sine of a sum of angles C and D is given by
sin(C+D)=sinC.cosD+cosC.sinD\sin (C+D)=\sin C.\cos D+\cos C.\sin D, then the value of sin75\sin {{75}^{\circ }} is?
a)122(3+1)\dfrac{1}{2\sqrt{2}}\left( \sqrt{3}+1 \right)
b) 12(31)\dfrac{1}{2}\left( \sqrt{3}-1 \right)
c) 32\dfrac{\sqrt{3}}{2}
d)12\dfrac{1}{2}

Explanation

Solution

Hint: We should try to write 75{{75}^{\circ }}as a sum of angles whose sine and cosine values are known. Then, we can use the formula given in the question to find sin75\sin {{75}^{\circ }} in terms of the sine and cosine values of the other two angles.

Complete Complete step by step answer:


We can write 75{{75}^{\circ }} as the sum of 45 and 30{{45}^{\circ }}\text{ and 3}{{0}^{\circ }}, i.e.
75=45+30{{75}^{\circ }}={{45}^{\circ }}+{{30}^{\circ }}
Now, from the definition of sine cosine function, we know that, in a right angled triangle having sides a and b and hypotenuse h as shown in figure 1,
sin(θ)=length of side facing the angle thetalength of the hypotanuse=ah\sin (\theta )=\dfrac{\text{length of side facing the angle theta}}{\text{length of the hypotanuse}}=\dfrac{a}{h}
and cos(θ)=length of side adjacent to the angle thetalength of the hypotanuse=bh\cos (\theta )=\dfrac{\text{length of side adjacent to the angle theta}}{\text{length of the hypotanuse}}=\dfrac{b}{h}
To find the sine and cosine of 45 and 30{{45}^{\circ }}\text{ and 3}{{0}^{\circ }}, we can draw the triangles shown in figure 2 and figure 3.
So, sin(30)=12 and cos(30)=32\sin ({{30}^{\circ }})=\dfrac{1}{2}\text{ and }\cos ({{30}^{\circ }})=\dfrac{\sqrt{3}}{2} (from fig2)
And sin(45)=12 and cos(45)=12\sin ({{45}^{\circ }})=\dfrac{1}{\sqrt{2}}\text{ and }\cos ({{45}^{\circ }})=\dfrac{1}{\sqrt{2}} (from fig3)

Now, using the formula given in the question and using the values as derived above,
sin(75)=sin(45+30)=sin(45)cos(30)+sin(30)cos(45) =(12.32)+(12.12)=3+122 \begin{aligned} & \sin (75{}^\circ )=\sin (45{}^\circ +30{}^\circ )=\sin (45{}^\circ )\cos (30{}^\circ )+\sin (30{}^\circ )\cos (45{}^\circ ) \\\ & =\left( \dfrac{1}{\sqrt{2}}.\dfrac{\sqrt{3}}{2} \right)+\left( \dfrac{1}{2}.\dfrac{1}{\sqrt{2}} \right)=\dfrac{\sqrt{3}+1}{2\sqrt{2}} \\\ \end{aligned}
This answer matches option (a) of the question and thus option (a) is the correct answer.

Note: While finding the sines and cosines of various angles, we should try to write them in terms of 30{{30}^{\circ }}, 60{{60}^{\circ }} and 45{{45}^{\circ }} as their trigonometric ratios can be easily found out from figures 1 and 2.
In many cases, the angles have a value more than 360{{360}^{\circ }}. In that case, we can subtract a multiple of 360{{360}^{\circ }} from the original angle and find the sine and cosine of it as adding or subtracting 360{{360}^{\circ }} does not change the value of sine or cosine.