If the focal length of the eye-piece of a telescope is doubl... | Physics | SolveeIt | Solveeit

Today, August 23

Question

If the focal length of the eye-piece of a telescope is doubled, its magnifying power $(m)$ will be

A

$2m$

B

$3m$

C

$\frac{m}{2}$

D

$4m$

Answer

$\frac{m}{2}$

Explanation

Solution

We know the magnifying power (m) is given by $m=- \frac{f_0}{f_e}$
Now if the focal length of the eye-piece $(f_e)$ is doubled, then Now if the focal length of the eye-piece to
$m'= \frac{f_0}{2f_e} = \frac{m}{2}$