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Question

Physics Question on Ray optics and optical instruments

If the focal length of a lens of a camera is 5f5 f and that of another is 2.5f2.5\, f, what is the time of exposure for the second, if for the first one is 1200\frac{1}{200} s? (where ff is focal length/unit aperture)

A

1200\frac{1}{200}

B

1800\frac{1}{800}

C

16400\frac{1}{6400}

D

13200\frac{1}{3200}

Answer

1800\frac{1}{800}

Explanation

Solution

Ratio of time of expoiusers
t1t2=(f1f2)2=(5f2.5f)2\frac{t_{1}}{t_{2}}=\left(\frac{f_{1}}{f_{2}}\right)^{2}=\left(\frac{5 f}{2.5 f}\right)^{2}
1/200t2=(2)2\Rightarrow \frac{1 / 200}{t_{2}} =(2)^{2}
t2=1800s\Rightarrow t_{2}=\frac{1}{800} s