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Question: If the first and the (2n-1)th terms of an A.P., G.P. and H.P. are equal and their nth terms are a, b...

If the first and the (2n-1)th terms of an A.P., G.P. and H.P. are equal and their nth terms are a, b, c respectively , then

A

a+c = 2b

B

a+c = b

C

ac –b2 = 0

D

None of these

Answer

ac –b2 = 0

Explanation

Solution

Let α be the first and β be the (2n– 1) terms of an A.P., G.P. and H.P. Then α, a, β will be in A.P., α, b, β will be in G.P. α, c, β will be in H.P.

Hence a, b, c are respectively A. M. , G.M. and H.M. of α and β.

⇒ a =α+β2\frac { \alpha + \beta } { 2 }, b2 = αβ and c = 2αβα+β\frac { 2 \alpha \beta } { \alpha + \beta } .Hence ac-b2 =0