Question
Question: If the first and the (2n-1)th terms of an A.P., G.P. and H.P. are equal and their nth terms are a, b...
If the first and the (2n-1)th terms of an A.P., G.P. and H.P. are equal and their nth terms are a, b, c respectively , then
A
a+c = 2b
B
a+c = b
C
ac –b2 = 0
D
None of these
Answer
ac –b2 = 0
Explanation
Solution
Let α be the first and β be the (2n– 1) terms of an A.P., G.P. and H.P. Then α, a, β will be in A.P., α, b, β will be in G.P. α, c, β will be in H.P.
Hence a, b, c are respectively A. M. , G.M. and H.M. of α and β.
⇒ a =2α+β, b2 = αβ and c = α+β2αβ .Hence ac-b2 =0