Question
Mathematics Question on Sequence and series
If the first and the (2n−1)th term of an AP,GP and HP are equal and their nth terms are a,b and c respectively, then
A
a=b=c
B
a≥b≥c
C
a+c=b
D
ac−b2=0
Answer
ac−b2=0
Explanation
Solution
Since, first and (2n - 1)th terms are equal.
Let first term be x and (2n - 1)th term be y,
whose middle term is tn.
Thus, in arithmetic progression, tn=2x+y=a
In geometric progression, tn=xy=b
In harmonic progression, tn=x+y2xy=c
⇒b2=ac and a>b>c[usingAM>GM>HM]
Here, equality holds (i.e. a = b =c) only if all terms are
same. Hence, options (a), (b) and (d) are correct