If the events A and B be mutually exclusive, then P(A+B) wil... | MATH - USE OF PERMUTATIONS AND COMBINATIONS IN PROBABILITY | SolveeIt | Solveeit

Today, August 18

Question

If the events A and B be mutually exclusive, then P(A+B) will be equal to

A

P(1) + P(2)

B

P(1) – P(2)

C

P(1). P(2)

D

P(1)/P(2)

Answer

P(1) + P(2)

Explanation

Solution

For mutually exclusive events A and B,

AĒB = φ

Ž P(AĒB) = 0

\ P(A+B) or P(AUB) = P(1) + P(2)