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Question: If the events A and B are mutually exclusive, then \(P \left( \frac { A } { B } \right) =\)...

If the events A and B are mutually exclusive, then P(AB)=P \left( \frac { A } { B } \right) =

A

0

B

1

C

P(A∩B)P(A)\frac { P ( A \cap B ) } { P ( A ) }

D

P(A∩B)P(B)\frac { P ( A \cap B ) } { P ( B ) }

Answer

0

Explanation

Solution

P(AB)=P(A∩B)P(B)P \left( \frac { A } { B } \right) = \frac { P ( A \cap B ) } { P ( B ) }

Since AA and are mutually exclusive.

So, P(A∩B)=0P ( A \cap B ) = 0. HenceP(AB)=0P(B)=0P \left( \frac { A } { B } \right) = \frac { 0 } { P ( B ) } = 0