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Question

Physics Question on electrostatic potential and capacitance

If the equivalent capacitance between PP and QQ of the combination of the capacitors shown in figure below is 30μF30\,\mu \,F , the capacitor CC is

A

60μF60\,\mu F

B

30μF30\,\mu F

C

10μF10\,\mu F

D

5μF5\,\mu F

Answer

60μF60\,\mu F

Explanation

Solution

C=C1+C2+C3C'=C_{1}+C_{2}+C_{3}
=20+20+20=20+20+20
=60μF=60\,\mu F
1C=1C+160\frac{1}{C''}=\frac{1}{C'}+\frac{1}{60}
130=1C+160\frac{1}{30}=\frac{1}{C'}+\frac{1}{60}
1C=130160\frac{1}{C'}=\frac{1}{30}-\frac{1}{60}
1C=2160\frac{1}{C'}=\frac{2-1}{60}
1C=160\frac{1}{C'}=\frac{1}{60}
\Rightarrow C=60C'=60