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Question

Question: If the equilibrium constant for the given reaction is \(K_{a1} = K_{a2} = K_{a3}\) No \(K_{a1} < K_...

If the equilibrium constant for the given reaction is Ka1=Ka2=Ka3K_{a1} = K_{a2} = K_{a3}

No Ka1<Ka2<Ka3K_{a1} < K_{a2} < K_{a3} then the equilibrium constant for the reaction Ka1=Ka2+Ka3K_{a1} = K_{a2} + K_{a3} No will be

A

1

B

2

C

3

D

4

Answer

4

Explanation

Solution

: NO 12N2+12O2;Kc=0.25\frac{1}{2}N_{2} + \frac{1}{2}O_{2};K_{c} = 0.25

12N2+12O2\frac{1}{2}N_{2} + \frac{1}{2}O_{2} NO; Kc=10.25=4K_{c} = \frac{1}{0.25} = 4