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Question: If the equation x<sup>2</sup> – (2 + m) x + (m<sup>2</sup> – 4m + 4) = 0 has coincident roots, then-...

If the equation x2 – (2 + m) x + (m2 – 4m + 4) = 0 has coincident roots, then-

A

m = 0, m = 1

B

m = 0, m = 2

C

m = 2/3, m = 6

D

m = 2/3, m = 1

Answer

m = 2/3, m = 6

Explanation

Solution

Since roots are coincident, we have

(–(2 + m))2 – 4.1. (m2 – 4m + 4) = 0

⇒ 4 + m2 + 4m – 4m2 + 16m – 16 = 0

⇒ 3m2 – 20m + 12 = 0 ⇒ m = 2/3, 6.