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Question

Physics Question on Waves

If the equation of motion of standing waves is y=0.3sin(314t1.57x)y=0.3 \sin (314\, t-1.57\, x), then the velocity of standing wave will be :

A

400 m/s

B

300 m/s

C

200 m/s

D

100 m/s

Answer

200 m/s

Explanation

Solution

Here: Equation of the standing wave is y=0.3sin(314t1.57x)y=0.3 \sin (314\, t-1.57\, x) ...(1) The standard equation of standing wave is y=asin2π[tTxλ]y=a \sin 2 \pi \left[\frac{t}{T}-\frac{x}{\lambda}\right] ...(2) Comparing the given equation (1) and standard equation (2), we get y=0.3sin[314t2π1.57λ]y =0.3 \sin \left[\frac{314 t}{2 \pi}-\frac{1.57}{\lambda}\right] =0.30100sin2π(50tx4)=\frac{0.30}{100} \sin 2 \pi\left(50\, t-\frac{x}{4}\right) or 1T=50\frac{1}{T}=50 and λ=4\lambda=4 Hence, the velocity of the standing wave is v=nλ=1T×4=50×4=200m/sv=n \lambda=\frac{1}{T} \times 4=50 \times 4=200\, m / s