Question
Physics Question on Waves
If the equation of motion of standing waves is y=0.3sin(314t−1.57x), then the velocity of standing wave will be :
A
400 m/s
B
300 m/s
C
200 m/s
D
100 m/s
Answer
200 m/s
Explanation
Solution
Here: Equation of the standing wave is y=0.3sin(314t−1.57x) ...(1) The standard equation of standing wave is y=asin2π[Tt−λx] ...(2) Comparing the given equation (1) and standard equation (2), we get y=0.3sin[2π314t−λ1.57] =1000.30sin2π(50t−4x) or T1=50 and λ=4 Hence, the velocity of the standing wave is v=nλ=T1×4=50×4=200m/s