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Question: If the equation \(\frac{x^{2} - bx}{ax - c}\) = \(\frac{m - 1}{m + 1}\) has roots equal in magnitud...

If the equation x2−bxax−c\frac{x^{2} - bx}{ax - c} = m−1m+1\frac{m - 1}{m + 1} has roots equal in

magnitude but opposite in sign, then m =

A

a+ba−b\frac{a + b}{a - b}

B

a−ba+b\frac{a - b}{a + b}

C

b−ab+a\frac{b - a}{b + a}

D

None of these

Answer

a−ba+b\frac{a - b}{a + b}

Explanation

Solution

Coeff. of x = 0

⇒ – bm – am – b + a = 0

m = a–ba+b\frac{a–b}{a + b}