Question

If the equation for the displacement of a particle moving on a circular path is given by $(\theta)=$ $2 t^{3}+0.5$ where $\theta$ is in radians and $t$ in seconds, then the angular velocity of the particleat $t = 2\, sec$, is

• A. 24 rad/sec
• B. 12 rad/sec
• C. 8 rad/sec
• D. 36 rad/sec

Answer 1

Answer: (A)

24 rad/sec

Answer 2

Angular velocity, $\omega=\frac{d \theta}{d t}=6 t^{2}$ at $t=2\, sec$ $w=6 \times 4=24\, rad / sec .$