Question

If the enthalpy of a reversible reaction is 8.314 kJ/mol over the temperature range

400 K to 500 K. Therefore the value of

ln (K₅₀₀ / K₄₀₀) for the reaction is

• A. 1.0
• B. 2.0
• C. 2.5
• D. 0.5

Answer 1

Answer: (D)

0.5

Answer 2

ln = $\frac { \Delta \mathrm { H } } { \mathrm { R } }$ ×

= $\frac { 8.314 \times 10 ^ { 3 } \times ( 500 - 400 ) } { 8.314 \times 400 \times 500 }$ = 0.5