Solveeit Logo

Question

Physics Question on Capacitors and Capacitance

If the energy of a 100 πF\pi F capacitor charged to 6 kV could all be used to lift a 50 kg mass, hat would be the greatest vertical height through which mass could be raised?

A

0.6 mm

B

3.6 m

C

1.2 mm

D

12 m

Answer

3.6 m

Explanation

Solution

Energy stored in the capacitor is used in lifting the mass. \therefore mgh=12CV2mgh=\frac{1}{2}C{{V}^{2}} 50×9.8×h=1×100×106×(6×103)250\times 9.8\times h=1\times 100\times {{10}^{-6}}\times {{(6\times {{10}^{3}})}^{2}} 50×9.8×h=12×100×106×36×10650\times 9.8\times h=\frac{1}{2}\times 100\times {{10}^{-6}}\times 36\times {{10}^{6}} \therefore h=180050×9.8=3.6mh=\frac{1800}{50\times 9.8}=3.6\,m