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Question: If the emf of a thermocouple, one junction of which is kept 0°C is given by \(e = at + 1/2bt^{2}\) t...

If the emf of a thermocouple, one junction of which is kept 0°C is given by e=at+1/2bt2e = at + 1/2bt^{2} then the neutral temperature will be

A

a/b

B

– a/b

C

a/2b

D

–1/ ab

Answer

– a/b

Explanation

Solution

At neutral temperature, thermal emf will be maximum.

dedt=a+bt\therefore\frac{de}{dt} = a + bt

For maximum or minima, a+btn=0a + bt_{n} = 0

tn=a/b\therefore t_{n} = - a/b