Solveeit Logo

Question

Physics Question on Atoms

If the electron in a hydrogen atom jumps from an orbit with level n1=2n_{1} =2 to an orbit with level n2=1n_{2} =1 the emitted radiation has a wavelength given by

A

λ=53R\lambda = \frac{5}{3R}

B

λ=43R\lambda = \frac{4} {3R}

C

λ=R4\lambda = \frac{R}{4}

D

λ=3R4\lambda = \frac{3R}{4}

Answer

λ=43R\lambda = \frac{4} {3R}

Explanation

Solution

1λ=R(1n121n22)\frac{1}{\lambda}=R \left(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right)
=R(112122)=3R4=R\left(\frac{1}{1^{2}}-\frac{1}{2^{2}}\right)=\frac{3R}{4}
λ=43R\Rightarrow\, \lambda =\frac{4}{3R}