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Question: If the electric flux entering and leaving an enclosed surface respectively is \(\varphi_{1}\) and \(...

If the electric flux entering and leaving an enclosed surface respectively is φ1\varphi_{1} and φ2\varphi_{2} the electric charge inside the surface will be

A

(φ1+φ2)ε0(\varphi_{1} + \varphi_{2})\varepsilon_{0}

B

(φ2−φ1)ε0(\varphi_{2} - \varphi_{1})\varepsilon_{0}

C

(φ1+φ2)/ε0(\varphi_{1} + \varphi_{2})/\varepsilon_{0}

D

(φ2−φ1)/ε0(\varphi_{2} - \varphi_{1})/\varepsilon_{0}

Answer

(φ2−φ1)ε0(\varphi_{2} - \varphi_{1})\varepsilon_{0}

Explanation

Solution

φnet=1ε0×Qenc\varphi_{net} = \frac{1}{\varepsilon_{0}} \times Q_{enc} ⇒ Qenc=(φ2−φ1)ε0Q_{enc} = (\varphi_{2} - \varphi_{1})\varepsilon_{0}