Question

If the edge- length of the unit of Sodium chloride is 600 pm, and the ionic radius of Cl- ion is 190 pm, then the ionic radius of Na+ ion is

• A. 310 pm
• B. 110 pm
• C. 220 pm
• D. None

Answer 1

Answer: (B)

110 pm

Answer 2

$r_{Na^{+}} + r_{CI^{-}} = 600/2 = 300$

$r_{Na^{+}} = 300 - 190 = 110pm$