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Question: If the eccentricity of two ellipses \(\frac{x^{2}}{169}\)+ \(\frac{y^{2}}{25}\)= 1 and \(\frac{x^{2}...

If the eccentricity of two ellipses x2169\frac{x^{2}}{169}+ y225\frac{y^{2}}{25}= 1 and x2a2\frac{x^{2}}{a^{2}}+ y2b2\frac{y^{2}}{b^{2}}= 1 are equal then ab\frac{a}{b} =

A

513\frac{5}{13}

B

613\frac{6}{13}

C

135\frac{13}{5}

D

136\frac{13}{6}

Answer

513\frac{5}{13}

Explanation

Solution

1+b2a\sqrt{1 + \frac{b^{2}}{a}}= 1+25169\sqrt{1 + \frac{25}{169}}