Solveeit Logo

Question

Physics Question on Gravitation

If the Earth shrinks in its radius by 4%, mass remaining the same, the value of 'g' on its surface

A

decreases by about 4%

B

increases by about 8%

C

decreases by about 8%

D

remains constant

Answer

increases by about 8%

Explanation

Solution

We know, g=GMR2g = \frac{GM}{R^2}
Since G and M are constants, so g increases as R decreases
Δgg=ΔRR\frac{\Delta g}{g} = \frac{\Delta R}{R}
As ΔRR=4%\frac{\Delta R}{R} =4\%
So, Δgg=8%\frac{\Delta g}{g} = 8\%