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Question

Mathematics Question on Functions

If the domain of the function f(x)=[x]1+x2f(x)=\frac{[x]}{1+x^2}, where [x][x] is greatest integer ≤x\leq x, is [2,6)[2,6), then its range is

A

(537,25]\left(\frac{5}{37}, \frac{2}{5}\right]

B

\left(\frac{5}{26}, \frac{2}{5}\right]-\left\\{\frac{9}{29}, \frac{27}{109}, \frac{18}{89}, \frac{9}{53}\right\\}

C

(526,25]\left(\frac{5}{26}, \frac{2}{5}\right]

D

\left(\frac{5}{37}, \frac{2}{5}\right]-\left\\{\frac{9}{29}, \frac{27}{109}, \frac{18}{89}, \frac{9}{53}\right\\}

Answer

(537,25]\left(\frac{5}{37}, \frac{2}{5}\right]

Explanation

Solution

If the domain of the function fx=$$$x/1+x2$, where x$$ is greatest integer ≤ x, is [2,6), then its range is

So, the correct answer is (A): (537,25]\left(\frac{5}{37}, \frac{2}{5}\right]