Solveeit Logo
Login

Question

Question: If the displacement of a particle executing SHM is given by \(y = 0.30\sin(220t + 0.64)\) in metre, ...

If the displacement of a particle executing SHM is given by y=0.30sin⁡(220t+0.64)y = 0.30\sin(220t + 0.64) in metre, then the frequency and maximum velocity of the particle is

A

35 Hz, 66 m / s

B

45 Hz, 66 m / s

C

58 Hz, 113 m / s

D

35 Hz, 132 m / s

Answer

35 Hz, 66 m / s

Explanation

Solution

n=ω2π=2202π=35Hzn = \frac{\omega}{2\pi} = \frac{220}{2\pi} = 35Hz

vmax⁡v_{\max}