Question
Mathematics Question on introduction to three dimensional geometry
If the direction consines of a vector of magnitude 3 are 32,3−a,32,a>0 then the vector is
A
2i^+j^+2k^
B
2i^−j^+2k^
C
i^−2j^+2k^
D
i^+2j^−2k^
Answer
2i^−j^+2k^
Explanation
Solution
Required vector = 3(li^+mj^+nk^) Where l2+m2+n2 = 1 ⇒ 94+9a2+94=1 ⇒ 9a2+98=1 ⇒ a2=1⇒a=1 Required vector = 3 (32i^−31j^+32k^) = 2i^−j^+2k^