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Physics Question on physical world

If the dimensions of a physical quantity are given by [MaLbTc][M^{a}L^{b}T^{c}], then the physical quantity will be

A

velocity if a=1, b=0, c=−1a = 1,\, b = 0,\, c = - 1

B

acceleration if a=1, b=1, c=−2a = 1,\, b = 1,\, c = - 2

C

force if a=0, b=−1, c=−2a = 0,\, b = - 1,\, c = - 2

D

pressure if a=1, b=−1, c=−2a = 1,\, b = - 1,\, c = - 2

Answer

pressure if a=1, b=−1, c=−2a = 1,\, b = - 1,\, c = - 2

Explanation

Solution

[P]=FA=[MLT−2L2][ P ]=\frac{ F }{ A }=\left[\frac{ MLT ^{-2}}{ L ^{2}}\right] =[ML−1T−2]=\left[ ML ^{-1} T ^{-2}\right]