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Question: If the difference of the roots of \(ax^{2} + bx + c = 0\) be 2, then the value of p is....

If the difference of the roots of ax2+bx+c=0ax^{2} + bx + c = 0 be 2, then the value of p is.

A

x1,x2,x3x_{1},x_{2},x_{3}

B

a=b=0,cRa = b = 0,c \in R

C

a=c=0,bRa = c = 0,b \in R

D

b24ac0b^{2} - 4ac \geq 0

Answer

a=c=0,bRa = c = 0,b \in R

Explanation

Solution

As given, if 5,155,\frac{1}{5} are the roots, then 7,177,\frac{1}{7} and xx

x23x+3x^{2} - 3x + 3

(3,3/2)( - 3,3/2)