Question
Question: If the difference of the roots of \(ax^{2} + bx + c = 0\) be 2, then the value of p is....
If the difference of the roots of ax2+bx+c=0 be 2, then the value of p is.
A
x1,x2,x3
B
a=b=0,c∈R
C
a=c=0,b∈R
D
b2−4ac≥0
Answer
a=c=0,b∈R
Explanation
Solution
As given, if 5,51 are the roots, then 7,71 and x
x2−3x+3
⇒ (−3,3/2)