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Question: If the derivative of the function \(\lim_{n \rightarrow \infty}\)is everywhere continuous and differ...

If the derivative of the function limn\lim_{n \rightarrow \infty}is everywhere continuous and differentiable at x = 1 then

A

a = 2, b = 3

B

a = 3, b = 2

C

a = –2, b = – 3

D

a = – 3, b = – 2

Answer

a = 2, b = 3

Explanation

Solution

To find a, b we must have two equations in a, b

Since f(x)f ( x ) is differentiable, it must be continuous at x=1x = - 1.

\therefore R=L=VR = L = V at x=1x = - 1 for f(x) ba+4=a+b\Rightarrow b - a + 4 = a + b

2a=4\therefore 2 a = 4 \quad i.e., a=2a = 2

Again f(x)f ^ { \prime } ( x ) is continuous, it must be continuous at x=1x = - 1.

R=L=V\therefore R = L = V at x=1x = - 1 for f(x)f ^ { \prime } ( x )

2b+a=2a- 2 b + a = - 2 a Putting a=2a = 2 we get 2b+2=4- 2 b + 2 = - 4

2b=6\therefore 2 b = 6 or b=3b = 3