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Question: If the De –Broglie wavelength of an electron in first Bohr's orbit be l then the minimum radial dist...

If the De –Broglie wavelength of an electron in first Bohr's orbit be l then the minimum radial distance between the electrons in the first and second Bohr's orbit is –

A

l

B

λ2\frac{\lambda}{2}

C

2l

D

λ2π\frac{\lambda}{2\pi}

Answer

λ2π\frac{\lambda}{2\pi}

Explanation

Solution

2p r = nl or r = nλ2π\frac{n\lambda}{2\pi}

r2 – r 1 = 2λ2π\frac{2\lambda}{2\pi} – λ2π\frac{\lambda}{2\pi} = λ2π\frac{\lambda}{2\pi}